# Fraction & Decimal Number

# Fraction & Decimal Number

#### Question 1:

In the table below, write the place value of each of the digits in the number 378.025.

Place |
Hundreds |
Tens |
Units |
Tenths |
Hundredths |
Thousandths |

100 | 10 | 1 | 110110 | 11001100 | 1100011000 | |

Digit |
3 | 7 | 8 | 0 | 2 | 5 |

Place value |
300 | 010=0010=0 | 51000=0.00551000=0.005 |

#### ANSWER:

Place |
Hundreds |
Tens |
Units |
Tenths |
Hundredths |
Thousandths |

100 | 10 | 1 | 110110 | 11001100 | 1100011000 | |

Digit |
3 | 7 | 8 | 0 | 2 | 5 |

Place value |
300 | 7 × 10 = 70 |
8 × 1 = 8 |
010=0010=0 | 2100=0.022100=0.02 | 51000=0.00551000=0.005 |

#### Question 2:

Solve.

(1) 905.5 + 27.197

(2) 39 + 700.65

(3) 40 + 27.7 + 2.451

#### ANSWER:

(i)

932.697

(ii)

739.65

(iii)

= 70.151

#### Question 3:

Subtract.

(1) 85.96 – 2.345

(2) 632.24 – 97.45

(3) 200.005 – 17.186

#### ANSWER:

(i)

82.615

(ii)

534.79

(iii)

182.819

#### Question 4:

Avinash travelled 42 km 365 m by bus, 12 km 460 m by car and walked 640 m. How many kilometres did he travel altogether? (Write your answer in decimal fractions.)

#### ANSWER:

Distance travelled by bus = 42 km 365 m = 42 km + 365 m = 42 km + 36510003651000 km = 42 km + 0.365 km = 42.365 km (1 km = 1000 m)

Distance travelled by car = 12 km 460 m = 12 km + 460 m = 12 km + 46010004601000 km = 12 km + 0.460 km = 12.460 km

Distance travelled by walking = 640 m = 64010006401000 km = 0.640 km

∴ Total distance travelled altogether

= Distance travelled by bus + Distance travelled by car + Distance travelled by walking

= 42.365 km + 12.460 km + 0.640 km

= 55.465 km

+41512205....13464664650051142.36512.460+0.64055.465

Thus, the total distance travelled by Avinash altogether is 55.465 km.

Ayesha bought 1.80 m of cloth for her salwaar and 2.25 m for her kurta. If the cloth costs 120 rupees per metre, how much must she pay the shopkeeper?

#### ANSWER:

Length of cloth bought for salwaar = 1.80 m

Length of cloth bought for kurta = 2.25 m

∴ Total length of cloth bought

= Length of cloth bought for salwaar + Length of cloth bought for kurta

= 1.80 m + 2.25 m

= 4.05 m

+1124...82005511.80+2.254.05

Rate of cloth = Rs 120/m

∴ Amount paid to the shopkeeper

= Total length of cloth bought × Rate of cloth

= 4.05 m × ₹ 120/m

= ₹ 486

44×8084101560200×0500××0405×120000810×405××48600

Thus, Ayesha paid ₹ 486 to the shopkeeper.

#### Question 6:

Sujata bought a watermelon weighing 4.25 kg and gave 1 kg 750g to the children in her neighbourhood. How much of it does she have left?

#### ANSWER:

Total weight of the watermelon = 4.25 kg

Weight of the watermelon given to the children = 1 kg 750 g = 1 kg + 750 g = 1 kg + 75010007501000 kg = 1 kg + 0.75 kg = 1.75 kg

∴ Weight of the watermelon left with her

= Total weight of the watermelon − Weight of the watermelon given to the children

= 4.25 kg − 1.75 kg

= 2.5 kg

−4312...2127555043.2125-1.752.50

Thus, the weight of watermelon left with Sujata is 2.5 kg.

#### Question 7:

Anita was driving at a speed of 85.6 km per hour. The road had a speed limit of 55 km per hour. By how much should she reduce her speed to be within the speed limit?

#### ANSWER:

Original driving speed of Anita = 85.6 km/h

Speed limit for driving = 55 km/h

∴ Speed reduced by her to be within the speed limit

= Original driving speed of Anita − Speed limit for driving

= 85.6 km/h − 55 km/h

= 30.6 km/h

−853550...60685.6-55.030.6

Thus, Anita needs to reduce her speed by 30.6 km/h to be within the speed limit.

Practice